Nice work! I got a few mistakes when compared to your model answer. Some answers may need your double check:- Q4(a)(iii) As Susannah continue only 10Km per week after reaching 10Km in week 13. So will the answer be 201.5Km? Q7(a)(ii) t=7pi/12, about 1.8s. Q8(a) k is 0.193184734 and then P is about 2.503 E10

thank you! does anyone can do 2011 HSC maths?? im kidda stuck from question 9,.. few from question 1-8.. please send me a email church0419@naver.com if u got the solution for 2011 HSC 2unit maths thank you!! T..T!!

Nice work! I got a few mistakes when compared to your model answer. Some answers may need your double check:-

ReplyDeleteQ4(a)(iii) As Susannah continue only 10Km per week after reaching 10Km in week 13. So will the answer be 201.5Km?

Q7(a)(ii) t=7pi/12, about 1.8s.

Q8(a) k is 0.193184734 and then P is about 2.503 E10

Cheers,

Raymond

There is a mistake in Q1 (f) with r=-1/3 not 1/3 so there is something wrong with subsitution into formula. Actual answer would be 3/4 instead of 3/2.

ReplyDeletethank you!

ReplyDeletedoes anyone can do 2011 HSC maths??

im kidda stuck from question 9,.. few from question 1-8..

please send me a email church0419@naver.com if u got the solution for 2011 HSC 2unit maths thank you!! T..T!!